LECTURE 23

Dimensional Analysis

Units as a reasoning tool — checking, deriving, and transforming equations

The Hook

A student derives that the period of a pendulum is \(T = 2\pi\sqrt{g/L}\).

Something is wrong. How do you know without doing any physics?

Check the units: \([g/L] = (m/s^2)/m = 1/s^2\), so \([\sqrt{g/L}] = 1/s\).

But period should have units of seconds, not \(1/seconds\)!

The correct formula must be \(T = 2\pi\sqrt{L/g}\).

Physical equations must be dimensionally consistent. You cannot add meters to seconds. Every term in an equation must have the same dimensions. This is not just a check — it's a constraint that limits what equations are possible.

1. Dimension Checker

Enter the dimensions of each side to verify dimensional consistency.

Interactive Dimension Checker
Left: M¹L²T⁻²
Right: M¹L²T⁻²
✓ Dimensionally Consistent

Common Quantity Dimensions

QuantityDimensionsSI Unit
EnergyM L² T⁻²J = kg·m²/s²
ForceM L T⁻²N = kg·m/s²
PressureM L⁻¹ T⁻²Pa = N/m²
VelocityL T⁻¹m/s
AccelerationL T⁻²m/s²
FrequencyT⁻¹Hz = 1/s
Diffusion coef.L² T⁻¹m²/s
ViscosityM L⁻¹ T⁻¹Pa·s

2. Scaling Laws

Dimensional analysis reveals how quantities scale with size.

Surface Area vs Volume Scaling
10⁻⁶ to 1 m

Key insight: Small objects have higher surface-to-volume ratio.

• Nanoparticles: more reactive (more surface per volume)

• Catalysts: finely divided for maximum surface

• Small animals: lose heat faster

3. Diffusion Time

Time to diffuse distance \(L\): \(t \sim L^2/D\)

Diffusion Time Calculator

4. Unit Converter

Convert between common chemistry energy units.

Energy Unit Converter
Result: 0.518 eV

Common Chemistry Conversions

QuantityConversion
Energy1 eV = 96.485 kJ/mol = 8065.5 cm⁻¹
Energy1 Hartree = 27.21 eV = 627.5 kcal/mol
Length1 Å = 10⁻¹⁰ m = 100 pm
Pressure1 atm = 101.325 kPa = 760 Torr
Amount1 mol = 6.022 × 10²³ particles

5. Linearization

Transform nonlinear equations for easier analysis.

Linearization Explorer
1.0

6. Fermi Estimation

Combine dimensional analysis with rough estimates.

Water Molecules in a Raindrop
1.0 mm

Summary

Dimensional Analysis Uses

Check equationsAll terms same dimensions
Derive relationshipsMatch exponents
Identify scalingForm dimensionless groups
Catch errorsQuick sanity check
EstimateOrder of magnitude

Formula Manipulation

LogarithmLinearize exponentials
ReciprocalLinearize Langmuir, M-M
RearrangeIsolate desired variable
SubstituteConnect different forms

Key Insight: Units are not just labels — they carry information. Respecting dimensional consistency is the first line of defense against errors and a powerful tool for discovery.

Exercises

  1. Verify that \(PV = nRT\) is dimensionally consistent.
  2. Derive how the frequency of a vibrating string depends on length, tension, and linear density.
  3. How long to diffuse 1 cm in water (\(D \approx 10^{-9}\) m²/s)?
  4. Convert 2.5 eV to kJ/mol.