LECTURE 21

Distributions

How probability spreads across states

The Hook

In a gas at room temperature, molecules move at different speeds:

Question: What determines this spread? Why this particular shape?

Answer: The Boltzmann distribution — nature's way of spreading energy across states.

The Boltzmann Distribution

At thermal equilibrium, the probability of a system being in state i with energy Ei is:

$$P_i = \frac{g_i e^{-E_i/k_BT}}{Z}$$

where Z = Σ gᵢ e-Eᵢ/kBT is the partition function

The Boltzmann Factor

The heart of the distribution: e-E/kBT

The Boltzmann distribution is the most probable distribution — it maximizes entropy subject to constraints (fixed average energy).

Interactive: Two-Level System

Population vs Temperature: Ground (E=0) and Excited (E=ε) States
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P₀ (ground)
-
P₁ (excited)
-
P₁/P₀
-
T where kBT = ε
500
300
P₀ (ground)
P₁ (excited)
kBT = ε

Population Ratio

$$\frac{P_j}{P_i} = e^{-(E_j - E_i)/k_BT}$$

The ratio depends only on the energy difference.

The Maxwell-Boltzmann Speed Distribution

$$f(v) = 4\pi \left(\frac{m}{2\pi k_BT}\right)^{3/2} v^2 e^{-mv^2/(2k_BT)}$$
Molecular Speed Distribution
-
vmp (m/s)
-
⟨v⟩ (m/s)
-
vrms (m/s)
300
vmp = √(2RT/M)
⟨v⟩ = √(8RT/πM)
vrms = √(3RT/M)

Why the v² factor? In 3D, there are more ways to have high speed than low — the number of velocity states with speed v is proportional to the surface area of a sphere: 4πv². This competes with the Boltzmann factor e-mv²/2kT.

Speed Formula Meaning
vmp√(2kBT/m)Peak of distribution
⟨v⟩√(8kBT/πm)Average speed
vrms√(3kBT/m)√⟨v²⟩, relates to kinetic energy

Order: vmp < ⟨v⟩ < vrms (always!)

The Gaussian (Normal) Distribution

$$f(x) = \frac{1}{\sigma\sqrt{2\pi}} e^{-(x-\mu)^2/(2\sigma^2)}$$
Gaussian Distribution with 68-95-99.7 Rule
0
1

The 68-95-99.7 Rule

RangeProbability
μ ± 1σ68.3%
μ ± 2σ95.4%
μ ± 3σ99.7%

Central Limit Theorem: The sum of many independent random variables approaches a Gaussian, regardless of the original distributions. This is why Gaussians appear everywhere — measurement errors, thermal fluctuations, diffusion.

Rotational Population Distribution

$$P_J \propto (2J+1) e^{-BJ(J+1)/k_BT}$$

The degeneracy factor (2J+1) causes the peak at J > 0!

Rotational State Populations
-
Jmp
-
kBT (cm⁻¹)
2
300
Why Jmp > 0?

The degeneracy (2J+1) increases with J, but the Boltzmann factor decreases. These compete:

  • Low J: low degeneracy but high Boltzmann factor
  • High J: high degeneracy but low Boltzmann factor
  • Peak: where they balance

$$J_{mp} \approx \sqrt{\frac{k_BT}{2B}} - \frac{1}{2}$$

Chemistry Applications

Arrhenius Equation

$$k = A e^{-E_a/RT}$$

This is a Boltzmann factor! Only molecules with E ≥ Ea can react.

Spectral Line Intensities

Absorption intensity from level i to j depends on:

$$I_{i \to j} \propto N_i \cdot |\mu_{ij}|^2$$

Population Ni follows the Boltzmann distribution!

Doppler Broadening

Spectral lines are broadened due to molecular motion:

$$I(\nu) \propto e^{-mc^2(\nu - \nu_0)^2/(2k_BT\nu_0^2)}$$

A Gaussian shape with width ∝ √T

Summary: Key Distributions

Distribution Domain Key Parameter Use
BoltzmannDiscrete stateskBTEnergy state populations
GaussianContinuous, unboundedσ (width)Errors, fluctuations
Maxwell-Boltzmannv ≥ 0T and mMolecular speeds
PoissonNon-negative integersλ (rate)Rare events
Exponentialt ≥ 0λ (rate)Waiting times